+2c and +6c two charges are repelling each other with a force of 12 n .if each charge is given -2c of charge ,then the value of the force will be
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Hii..
F=Kq1q2/r²
q1=2C ,q2=6C
Now if -2C charge is added then
q1=0(neutral) ,q2=6-2=4C
Now,
If we put the values of q1 and q2 in the formula
F=K(0)(4)/r²
=0
Hence value of force is zero.
_____________________
Hope this helps!
F=Kq1q2/r²
q1=2C ,q2=6C
Now if -2C charge is added then
q1=0(neutral) ,q2=6-2=4C
Now,
If we put the values of q1 and q2 in the formula
F=K(0)(4)/r²
=0
Hence value of force is zero.
_____________________
Hope this helps!
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