Question

+2C charge and +6C charges are repelling each other with a force of 24N. If each charge is given -1C of charge, then the force is



Lütfen birini seçin:
a. 5N (Atrractive)
b. 10N (Attractive)
c. 12N (Repulsive )
d. 10N (Repulsive )
e. 20N (Repulsiv

Answer 1

Given:

+2C charge and +6C charges are repelling each other with a force of 24N. If each charge is given -1C of charge.

To find:

Value of force ?

Calculation:

In the 1st case:

$\therefore \: F_{1} = \dfrac{k(2)(6)}{ {d}^{2} } = 24 \: N$

$\implies \: \dfrac{k \times 12}{ {d}^{2} } = 24$

$\implies \: \dfrac{k}{ {d}^{2} } = 2 \: \: \: \: \: .....(1)$

In the 2nd case :

• 1st charge becomes 2 - 1 = 1 C
• 2nd charge becomes 6 - 1 = 5 C

$\therefore \: F_{2} = \dfrac{k(1)(5)}{ {d}^{2} }$

$\implies\: F_{2} = \dfrac{k \times 5}{ {d}^{2} }$

$\implies\: F_{2} = \dfrac{k }{ {d}^{2} } \times 5$

$\implies\: F_{2} = 2 \times 5$

$\implies\: F_{2} = 10 \: N$

Since both charges are positive , hence force will be repulsive.

So, net force will be 10 N (repulsive).