2C(s)+O2 gives to Co2(g)+Q calculate the volume of carbon dioxide liberated at STP
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The balanced chemical equation is, Na
2
CO
3
+2HCl→2NaCl+CO
2
+H
2
O.
1 mole of sodium carbonate (106 g) will produce 1 mol (22.4 L at STP) of carbon dioxide.
Thus, 2.12 g (
106
2.12
mol) of sodium carbonate will produced (
106
2.12
×22.4=0.448L) at STP of carbon dioxide.
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