Question

2ch3oh + 3o2 2co2 + 4 h2o if 3 g of methanol are used up in the combustion process, how many mole of water is produced?

Answer 1

♣ ANSWER:-

Well, we need a stoichiometrically balanced equation to represent the combustion … and as always, we (i) balance the carbons as carbon dioxide; (ii) balance the hydrogens as water; and (iii) balance the oxygens as dioxygen gas…

H3COH(l)+32O2(g)⟶CO2(g)+2H2O(l)

And thus we get 2 equiv water per equiv methanol combusted…

nMeOH=209∙g32.04∙g∙mol−1=6.52∙mol

And so we need 32 equiv of dioxygen gas, i.e. 9.78∙mol , a mass of approx 313∙g . And we get approx 13∙mol of water … i.e. a mass of 235∙g

hopefully it helps