Physics, asked by riyamalviy, 1 year ago

2charges each of 5m are placed in air at 0.15m distance apart calculate coulombian force acting
between them

Answers

Answered by 7255987278

3

F=Qq/4π€r²
F=9×10^9 ×5/(0.15)²
F=2×10¹²N.
thanks
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