Question

2cos^2 0°+ 1/3 sin^2 30°- 1/3 tan^2 60°​

Answer 1

Cos 0 = 1

Sin 30 = 1/2

Tan 60 =

$\sqrt{3}$

$2 \times 1 + \frac{1}{3} \times \frac{1}{4} - \frac{1}{3} \times { \sqrt{3} }^{2}$

$2 + \frac{1}{12} - 1$

$1 + \frac{1}{12}$

$\frac{12 + 1}{12}$

$\frac{13}{12}$