Math, asked by moulya3847, 1 year ago

(2cos^2theta-1)^2÷cos^4theta-sin^4theta=1-2sin^2theta

Answers

Answered by jaygoyal
0
wrong sum................please check properly
Answered by SagarSuman
0
so its cos2theta^2 ÷ (cos^2theta-sin^2theta)(cos^2theta + sin^2theta)
= cos2theta^2 ÷(cos^2theta-sin^2theta)
=cos2theta^2÷cos2theta
=cos2theta(LHS)

RHS=cos2theta
hence proved
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