(2cos^2theta -1)/(sin theta cos theta)=cot theta- tan theta
Prove that
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Step-by-step explanation:
Solving LHS:
(2cos^2 theta - 1)/sin theta con theta
= cos^2 theta + cos^2 theta - 1/sin theta cos theta
= cos^2 theta - sin^2 theta/sin theta cos theta (since sin^2 theta + cos^2 theta = 1)
= ( cos theta / sin theta ) - ( sin theta/ cos theta )
= cot theta -tan theta
= RHS
Hence Proved
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