Question

2cos(π/4+x)sin(π/4-x)=1-2sinxcosx

Answer 1

Answer :

by using formulae of cos(a+b) sin(a-b)

we can solve question

Answer 2

Step-by-step explanation:

Π=180°

Π/4=180°=45°

2cos(45°+x)sin(45°-x)=1-2sin x cos x

=>cos(45°+x)sin(45°-x)=1/2-sinxcosx

=>cos45°cosx+sin45°sinx × sin45^cosx+cos45°sinx=1/2-sinxcosx

=>1/√2.cosx+1/√2.sinx × 1/√2.cosx+1/√2sinx=1/2-sinx cosx

=>cosx/√2+sinx/√2 × cosx/√2sinx/√2=1/2-sinxcosx

=>sinxcosx/2×sinxcosx/2=1/2-sinxcosxs

=>sin^2xcos^2x/4=1/2-sinxcosx

=>sin^2xcos^2x=2-4sinxcosx

follow me