Math, asked by Tanvi12374, 12 days ago

2cos 67° /sin23°-tan40°/cot50°-cos0°

Answers

Answered by babyjai

0

Answer:

2cos67°/sin23°-tan40°/cot50°-cos0°

2sin(90°-67°)/sin23°-cot(90°-40°)/cot50°-1

2sin 23°/sin23°-cot50°/cot50°-1

2-1-1=2-2

=0.

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