Question

2cos 67° /sin23°-tan40°/cot50°-cos0°​
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Answer 1

Answer:

see below

Step-by-step explanation:

=2cos 67°/sin 23°- tan40°/cot50°-cos0°

=2 cos67°/sin (90-23)-tan40°/cot (90-50)-cos 0°

=2 cos 67°/cos 67°-tan 40°/tan 40°-cos 0°

2 cos 67°/cos 67°=2-tan 40°/tan 40°=1-cos 0°=1

=2-1-1

=0