Question

2cos(A-B)=2sin(A+B)=root 3​

Answer 1

Answer:

2cos(A-B) = 2sin(A+B) = √3

=> cos(A-B) = sin(A+B) = √3/2

=> cos (A-B) = √3/2 and sin(A+B) = √3/2

=> cos(A-B) = cos 30° and sin(A+B) = sin 60°

=> A-B = 30° and A+B = 60

=> A-B+A+B = 30+60=90

=> 2A = 90

=> A = 45 ° and B = 60-A = 60-45= 15°