Math, asked by wecwc8013, 9 months ago

2cos[(C+D)/2]sin[(C-D)/2] is equal to

A) sinC + sinD B) sinC - sinD C) cosC - cosD D) cosC + cosD

Answers

Answered by Anonymous
2

Step-by-step explanation:

2cos[(C+D)/2]sin[(C-D)/2]

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