Question

2cos sq theta + 2/1+ cot sq Theta is equal
to?

Answer 1

L.H.S. = (1+cot

2

θ)(1−cosθ)(1+cosθ)

⇒ L.H.S. = (1+cot

2

θ)(1−cos

2

θ)

⇒ L.H.S. = cosec

2

θsin

2

θ

[∵1+cot

2

θ=cosec

2

θand1−cos

2

θ=sin

2

]

⇒ L.H.S. = cosec

2

θsin

2

θ

⇒ L.H.S. =

sin

2

θ

1

×sin

2

θ=1=R.H.S. [∵cosecθ

sinθ

1

∴cosec

2

θ

sinθ

1

]

Answer 2

Answer:

Answer is 2

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