2cos square x+3sinx=0 plea solve it
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>>. 2cos^2x+3sinx=0
>>. 2(1 – sin2 x) + 3 sin x = 0
>>. 2 – 2 sin2x + 3 sin x = 0
>>. 2 sin2x – 3 sin x – 2 = 0
>>. 2 sin2x – 4 sin x + sin x – 2 = 0
>>. 2 sin x (sin x – 2) + 1 (sin x – 2) = 0
>>. (sin x – 2) (2 sin x + 1) = 0
hence,sin X=2. and. sinx= -1/2
now,sin X ≠ 2
since,sin X always lies between -1 to +1.
therefore, sin X= -1/2
sin X=sin 7π/6
X=nπ+(-1)7π/6 {general solution}
【hope this will help ya ☺️】
>>. 2cos^2x+3sinx=0
>>. 2(1 – sin2 x) + 3 sin x = 0
>>. 2 – 2 sin2x + 3 sin x = 0
>>. 2 sin2x – 3 sin x – 2 = 0
>>. 2 sin2x – 4 sin x + sin x – 2 = 0
>>. 2 sin x (sin x – 2) + 1 (sin x – 2) = 0
>>. (sin x – 2) (2 sin x + 1) = 0
hence,sin X=2. and. sinx= -1/2
now,sin X ≠ 2
since,sin X always lies between -1 to +1.
therefore, sin X= -1/2
sin X=sin 7π/6
X=nπ+(-1)7π/6 {general solution}
【hope this will help ya ☺️】
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