2cos2x+sinx=0. Find the general solution.
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Answer:
Sinx = (1 ± √33)/8
Step-by-step explanation:
2cos2x+sinx=0. Find the general solution.
2(1 - 2Sin²x) + Sinx = 0
=> 2 - 4Sin²x + Sinx = 0
=> 4Sin²x - Sinx - 2 = 0
=> Sinx = (1 ± √1 + 32)/(2 * 4)
=> Sinx = (1 ± √33)/8
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