Math, asked by bishalm864, 1 year ago

2cos38/sin52+4tan40/cot50+12sec66/cosec24

Answers

Answered by dishagupta14
4

Answer:

You can see the answer in adjoining.

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Answered by kapilsir19
0

Answer:

2 \ \cos(38)  \div  \sin(52)  + 4 \tan(40)  \div  \cot(50)  + 12 \sec(66)  \div \csc(24)  \\  = 2 \sin(52)  \div  \sin(52)  + 4 \cot(50)  \div  \cot(50)  + 12 \csc(24)   \div  \csc(24)  \\  = 2 + 4 + 12 = 18

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