2cos4theta.sin7theta?
Answers
Answered by
1
2cos4theta.sin7theta
=sin{(11/2)theta}+sin{(3/2)theta}
here i used a formula
that
2sinAcosB=sin{(A+B)/2}+sin{(A-B)/2}
=sin{(11/2)theta}+sin{(3/2)theta}
here i used a formula
that
2sinAcosB=sin{(A+B)/2}+sin{(A-B)/2}
abc123456789:
How ??by 2 ??
i used formula
see in my answer
2SinACosB Sin(A+B) + Sin (A-B)
ok
So there is no by 2 right?
by 2 will came
How??
it is formula
Similar questions