Question

2cos67°÷sin23°-tan40°÷cot50°-sin90°​

Answer 1

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The given expression

= 2(cos 67o/sin 23o) - (tan 40o/cot 50o) - sin90o

= 2(cos (90o - 23o)/sin 23o) - tan (90o - 50o)/cot 50o - sin90o

= 2(sin 23o/sin 23o) - cot 50o/cot 50o - sin90o

= 2 - 1- 1 = 0

Answer 2

Answer:

The given expression

= 2(cos 67o/sin 23o) - (tan 40o/cot 50o) - sin90o

= 2(cos (90o - 23o)/sin 23o) - tan (90o - 50o)/cot 50o - sin90o

= 2(sin 23o/sin 23o) - cot 50o/cot 50o - sin90o

= 2 - 1- 1 = 0