Question

2cos67bysin23 - tan40bycot50+cot0​ please answer me​

Answer 1

1

Pls mark as brainliest

Answer 2

2 cos(90 -23)/ sin 23 - tan(90-50) /cot 50 +cot0
Sin23/sin23-cot50/cot50+cot 0
0-0+cot0
0-0+0
=0