Math, asked by drnishanth520, 11 months ago

2cos70°÷sin20°+cos55°cosec35°÷tan5°tan25°tan45°tan65°tan85°

Answers

Answered by thameshwarp9oqwi
3

2cos70°÷sin20°+cos55°cosec35°÷tan5°tan25°tan45°tan65°tan85°

==> 2cos(90-20) ÷ sin20 + cos(90-35)*1/sin 35 ÷ tan (90-85) tan (90-65)tan45°tan65°tan85°

==> 2(sin20)/sin 20 + sin 35 / sin 35  ÷ cot 85* cot 65 * tan45 * tan65°tan85°

==> 2 + 1  ÷ 1/tan 85* 1/tan 65 * tan 45 * tan65°tan85°

==> 2 + 1  ÷ tan 45

==> 3 ÷ 1/1

==> 3

ANSWER = 3

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