2cosA = 1 then find the value of cosecA and SinA.
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Answer:
cosecA=2/√3
sinA=√3/2
Explanation:
CosA=1/2=Base/perpendicular
therefore, H²=B²+P². [by Pythagoras theorem]
since, base=1, perpendicular=2
so, P²=2²-1²=4-1=3
so, P=√3
sinA=Perpendicular/Hypotenuse=√3/2
cosec= 1/SinA=2/√3
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