Question

2cosec²30°+x sin²60°-3/4tan²30°=10​

Answer 1

2cosec²30°+x sin²60°-3/4tan²30°=10

=>2 (2)^2 + x (√3/2)^2 - 3/4 (1/√3)^2 = 10

=> 8 + x 3/4 - 3/12 =10

=> x 3/4 = (24+3)/12

=> x = (27/12) × (4/3)

=> x = 3