Question

2cosec67/sec23-tan70/cot20-cos theta+tan38•tan52

Answer 1

◀ HERE'S ⏬ YOUR ANSWER▶

$2 \frac{cosec67}{sec23} - \frac{tan70}{cot20} + tan38.tan52 \\ = 2 \frac{sec23}{sec23} - \frac{cot20}{cot20} + cot52.tan52 \\ = 2 - 1 + 1 \\ = 2$

⏏ HOPE THIS ⬆ HELPS YOU⏏

Answer 2

Step-by-step explanation:

2cosec67°/sec(90°-67°)-tan70°/cot(90°-70°)-1+tan38°tan(90°-38°)

cos°=1

2cosec67°/cosec67°-tan70°/tan70°-1+tan38°cot38°

2-1-1+1=1