Question

2Cot A-B/2 / 1- tan^22A-B/2 =____ plz explain​

Answer 1

Answer:

SinA=mSinB

=> SinA/SinB=m

Now, taking RHS

(m+1)/(m−1)=(SinA/SinB+1)/(SinA/SinB−1)

=> (SinA+SinB)/(SinA−SinB)

Now, using formula,

S + S = 2 SC

S - S = 2 CS

SinA+SinB=2Sin(A+B/2).Cos(A−B/2)

SinA−SinB=2Cos(A+B/2).Sin(A−B/2)

Substituting the values in the equation, we get

(m+1)/(m−1)=2Sin(A+B/2).Cos(A−B/2)/2Cos(A+B/2).Sin(A−B/2)

=> tan(A+B/2).cot(A−B/2)

=> tan(A+B/2)/tan(A−B/2)

Step-by-step explanation:

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