2Cot A-B/2 / 1- tan^22A-B/2 =____ plz explain
Answers
Answered by
1
Answer:
SinA=mSinB
=> SinA/SinB=m
Now, taking RHS
(m+1)/(m−1)=(SinA/SinB+1)/(SinA/SinB−1)
=> (SinA+SinB)/(SinA−SinB)
Now, using formula,
S + S = 2 SC
S - S = 2 CS
SinA+SinB=2Sin(A+B/2).Cos(A−B/2)
SinA−SinB=2Cos(A+B/2).Sin(A−B/2)
Substituting the values in the equation, we get
(m+1)/(m−1)=2Sin(A+B/2).Cos(A−B/2)/2Cos(A+B/2).Sin(A−B/2)
=> tan(A+B/2).cot(A−B/2)
=> tan(A+B/2)/tan(A−B/2)
Step-by-step explanation:
hope it is helpful for you and please mark me brainiest please follow and give lots of thanks also
Answered by
0
Answer:
how many alpha numerals are there in the format gstin
Similar questions