Question

2cubes each of the volume 27cm^3 are joined end to end. find the L.S.A of the resulting cuboid. ​

Answer 1

Step-by-step explanation:

volume of one cube= s^3

27=s^3

s=∛27

s=3 cm

now length of the resulting cuboid=3+3=6 cm

breath=3 cm

height=3 cm

now ,

lateral surface area of cuboid =2h(l+b)

2×3(6+3)

6(9)

54 cm^2

total surface area of cuboid = 2(lb+lh+bh)

2(18+18+9)

2(45)

90 cm^2

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Answer 2

volume of cube = 27cm^3

side of cube = 3

length of resulting cubiod = 6 cm

breadth of resulting cubiod = 3cm

height of resulting cubiod = 3cm

formula of LSA of cubiod = 2( BH+HL )

now LSA = 2 ( 3*3 + 3*6 )

= 2 ( 9 + 18 )

= 2* 27

= 54

so LSA of cubiod is 54cm^2