Question

2cubes each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid.​

Answer 1

Volume of each cube = 64 cm^3

There are 2 cubes

Now,

Volume of one cube = s^3

64 = s^3

$\sqrt[3]{64} = s$

4 cm = side

Cuboid:-

Length = 4+4 = 8 cm

Breadth = 4 cm

Height = 4 cm

Surface area = 2 (lb + bh + hl)

= 2 (8×4 + 4×4 + 4×8)

= 2 (32+16+32)

= 2×80

= 160 cm^2

Answer:

Surface area of cube is 160 cm^2.