Math, asked by Raajeswari2793, 1 year ago

2dice are thrown at the same time and the product of no appeaaring is noted find the probability that the product is a prime number

Answers

Answered by rishank9612
0

Two dice are thrown,

S = (1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

n(S) = 36

Event A - product of numbers is a prime

number.

A = (1,2),(1,3),(1,5),(2,1),(3,1),(5,1)

n(A) = 6

probability p(A) = n(A)/n(S)

= 6/36

= 1/6

Thank u......

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