2dice are thrown at the same time and the product of no appeaaring is noted find the probability that the product is a prime number
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Two dice are thrown,
S = (1,1),(1,2),(1,3),(1,4),(1,5),(1,6),
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
n(S) = 36
Event A - product of numbers is a prime
number.
A = (1,2),(1,3),(1,5),(2,1),(3,1),(5,1)
n(A) = 6
probability p(A) = n(A)/n(S)
= 6/36
= 1/6
Thank u......
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