2digit number is reversed .the larger of the two numbers is divided vby the smaller one.what is the largest possible remainder
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Now let the two digit number be
(10x + y)
We need such a number which can give us greatest remainder by x/y or y/x
The number is reversed henceforth we find the number with greatest remainder and then reverse it to find our original number.
9 is the greatest one digit number and it's greatest remainder will be 8
So, our reversed 2 digit number is 98
Hence, by reversing we get our original one which is,"89"
The answer is 89
(10x + y)
We need such a number which can give us greatest remainder by x/y or y/x
The number is reversed henceforth we find the number with greatest remainder and then reverse it to find our original number.
9 is the greatest one digit number and it's greatest remainder will be 8
So, our reversed 2 digit number is 98
Hence, by reversing we get our original one which is,"89"
The answer is 89
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