Question

2feCl3 + 2H2O + y = 2feCl2+ H2SO4 + 2HCl find the value of y?​

Answer 1

Answer:

The answer is always SO2. but you can find and solve .

Answer 2

y in the equation $2FeCl_{3}+2H_{2}O+y \rightarrow 2FeCl_{2}+H_{2}SO_{4}+2HCl$ is $SO_{2}$.

Explanation:

• The given reaction is an example of redox reaction.
• $FeCl_{3}$ is  getting reduced to $FeCl_{2}$. Its oxidation state is getting changed from +3 to +2.
• The sulphuric acid is getting formed by the reaction of sulphur dioxide, $FeCl_{3}$  and water with.
• The missing compound is sulphur dioxide.
• y = SO₂.
• $2FeCl_{3}+2H_{2}O+SO_{2} \rightarrow 2FeCl_{2}+H_{2}SO_{4}+2HCl$