-2G
b. If the system creates 500 frames per second, this is
(1/2) frame per millisecond. The load is (1/2). In this
case S = G x 2
or S = 0.184 (18.4 percent). This
means that the throughput is 500 * 0.184 = 92 and that
only 92 frames out of 500 will probably survive. Note
that this is the maximum throughput case,
percentagewise.
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