Question

2g of Ferris sulphate crystal heated in a dry boiling tube
1 list any two change that would be observed

Answer 1

Answer:

Two changes will take place in such an experiment:

1) Thermal decomposition of $FeSO_{4}$ to $Fe_{2}O_{3}$ under the high heat.

2) Liberation of the gases $SO_{2}$ and $SO_{3}$.

Explanation:

• As we all know, the colour of the most commonly occuring $FeSO_{4}.7H_{2}O$ is pale green. But, as we heat it up, the water embedded in the crystalline structure of the Ferrous Sulphate slowly evaporates (assuming that the temperature is below $100$°C, if the temperature is > turning it from the Hepta-Hydrate state to the anhydrous state. This results in the change in colour of the Ferrous Sulphate from its characteristic pale green colour to white.

• However, if the crystals are heated to a high temperature for a prolonged period of time, they will start to decompose to Ferric Oxide. They decomposition is also accompanied by the liberation of Sulphur dioxide and Sulphur trioxide. The overall reaction is given below:

$FeSO_{4} + Heat$ ⇒ $Fe_{2}O_{3} + SO_{2} + SO_{3}$

Note: $SO_{2}$ and $SO_{3}$ are quite dangerous. $SO_{3}$ can react with water in the atmosphere to form $H_{2}SO_{4}$.

Answer 2

Answer:

hey!!

Explanation:

Following two observations are observed when crystals of ferrous sulphate are heated: (1) Change in state and color takes place. (2) A gas is evolved during this process. Since, the compound (ferrous sulphate) decomposes into two or more substances therefore, it is a decomposition reaction

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