Question

2g of H2 and 16 g O2 are reacted together.what is limiting reagent .calculate mass of water formed .

Answer 1

Answer:

Answer

Correct option is

B

18.0 g

H

2

+

2

1

O

2

→H

2

O

1 mole of H

2

combines with a half mole of O

2

to form one mole of H

2

O.

The molecular weights of H

2

, O

2

and H

2

O are 2 g/mol, 32 g/mol and 18 g/mole respectively.

2 g (1 mole) of H

2

combines with 16 g (half mole) of O

2

to form 18 g (one mole) of H

2

O.

We have 16.0 H

2

is mixed with 16.0g O

2

Out of this, 2.0 H

2

will combine with 16.0g O

2

since oxygen mass is limited.

18 g (one mole) of H

2

O will be obtained.