Question

2g sample containing in Na2CO and NaHCO3 loser 0.24 8 gram when heated to 300 degree Celsius the temperature at which an NaHCO3 composites to Na2CO3,Co2 and water what is the percentage of any Na2Co3 in the mixture

Answer 1

The chemical equation representing the decomposition of $NaHCO_{3}$ :

$2NaHCO_{3}(aq) -----> Na_{2}CO_{3}(aq) + H_{2}O (g) + CO_{2}(g)$

$CO_{2} and H_{2}O$ being gases are lost after decomposition.

Mass of the gases lost = 0.248 g

2 mol $NaHCO_{3}$ give 1 mol $CO_{2}$ and 1 mol $H_{2}O$

2 x 84 g $NaHCO_{3}$ give 44 g $CO_{2}$ and 18 g $H_{2}O$

Total mass of gaseous products = 18 + 44 g = 62 g

Mass of NaHCO3 that can give 0.248 g CO2 and H2O:

$0.248 g CO_{2} + H_{2}O$×$\frac{168 g NaHCO_{3}}{62 g H_{2}O+CO_{2}}$

= 0.672 g $NaHCO_{3}$

Mass % of $NaHCO_{3} = \frac{0.672 g}{2 g}*100$ = 33.6 %

Mass % of $Na_{2}CO_{3} = 100 - 33.6 = <u>66.4 % Na_{2}CO_{3}$

Answer 2

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Hey calculate in a calculator as I had done so no need to worry about the answer but sorry I have used calculator to calculate



Your answer is done


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