Question

2gm CO2 and 1gm H2O react to produce H2CO3 . Identify the limiting reagent and calculate the maximum amount of H2CO3 form and the amount of one of the left unreactend.​

Answer 1

Answer:

CO2 is the Limiting reagent

2.8182gm h2co3 will produce

0.1818gm of h20 remains left

Explanation:

Atomic mass of co2 is 44gm, h20 is 18gm and h2co3 is 62gm as the atomic mass of c=12gm,h=1gm & O=16gm

The reaction :

co2+h20=h2co3

so 44g co2 reacts with 18g h20

2g co2 reacts with 18*2/44=0.8182g

as 0.8182<1gm

so h20 will remain and co2 is the LR

The amount of h20 remains left is (1-0.8182)=0.1818gm

now 44g co2 produce 62g h2co3

2g co2 produce 62*2/44 =2.8182g h2co3