2gmof ice -25degree celcius .what is the heat required to raise the steam at 200degree celcius
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Answer:
Total energy required = 7063 Joules
Explanation:
Use the formula
q = m·ΔHf
where,
- q = heat energy = (2 g)x(334 J/g) = 668 J
- m = mass
- ΔHf = heat of fusion
Heat required to raise the temperature of -25°C water to 200°C water
q = mcΔT
⇒ q = (2 g)x(4.18 J/g·°C)[(200°C - -25°C)]
⇒ q = (2 g)x(4.18 J/g·°C)x(225°C)
⇒ q = 1881 J
Heat required to raise the temperature of -25°C water to 200°C water = 1881 J
Heat required to convert 100 °C water to 100 °C steam ,
q = m·ΔHv
where,
- q = heat energy
- m = mass
- ΔHv = heat of vaporization
⇒ q = (2 g) x (2257 J/g)
⇒ q = 4514 J
Heat required to convert 100°C water to 100°C steam = 4514 J
Total energy required,
⇒ q = 668 + 1881 + 4514
⇒ q = 7063 J
Total energy required = 7063 Joules
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