2grm of mixture of caco3 and mgco3 required 2grm of H2SO4 to complete reaction. determine the percentage composition of mixture ?
Answers
Answered by
3
Answer:
9+10=90 is the correct information
Answered by
1
Answer:
Amount of mixture of CaCO₃ and MgCO₃ = 2g
Amount of H₂SO₄ = 2g
To Find :
The percentage composition of the mixture
Solution :
The following reactions will take place
Molecular mass of MgCO₃ = 84gm
Molecular mass of CaCO₃ = 100gm
Molecular mass of H₂SO₄ = 98gm
Number of moles of acid
0.01 moles reacts with MgCO₃ and 0.01 moles react with CaCO₃
Percentage of MgCO₃ =
Percentage of CaCO₃ =
The percentage composition of the mixture is MgCO₃(42%) and CaCO₃(58%)
Explanation:
Similar questions