Chemistry, asked by AryaDuhaN, 10 months ago

2grm of mixture of caco3 and mgco3 required 2grm of H2SO4 to complete reaction. determine the percentage composition of mixture ?

Answers

Answered by monisushmakavila
3

Answer:

9+10=90 is the correct information

Answered by jackzzjck
1

Answer:

Amount of mixture of CaCO₃ and MgCO₃ = 2g

Amount of H₂SO₄ = 2g

To Find :

The percentage composition of the mixture

Solution :

   The following reactions will take place

         

   Molecular mass of MgCO₃ = 84gm

       Molecular mass of CaCO₃ = 100gm

       Molecular mass of H₂SO₄ = 98gm

   Number of moles of acid  

   0.01 moles reacts with MgCO₃ and 0.01 moles react with CaCO₃

   Percentage of MgCO₃ =

       Percentage of CaCO₃ =  

The percentage composition of the mixture is MgCO₃(42%) and CaCO₃(58%)

Explanation:

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