Physics, asked by shankarurugonda123, 4 months ago

2H2(g)+O2(g)? 2H2O(1) calculate the number of hydrogen molecules participated in above reacton?

Answers

Answered by mrpaul5

0

Answer:

2 mole Hydrogen gas participated in reaction

So 2 × 6.022 × 10^23 = 12.044 × 10^23 molecules participated in the reaction

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