2H2 + O2 → 2H2O
AH = +285.5 kJ mol-1
What will be the enthalpy change in the above reaction?
A) 205.5 kJ/mol
C) -205.5 kJ/mol
B) Zero kJ/mol
D) 1 kJ/mol
Answers
Answered by
3
Explanation:
The enthalpy change for the following reaction is -483.6 kJ:
2H2 (g) + O2 (g) → 2H2O (g)
Therefore, the enthalpy change for the following reaction is __________ kJ:
4H2 (g) + 2O2 (g) → 4H2O (g)
a. 483.6
b. -967.2
c. 967.2
d. 2.34 x 10^5
e. -483.6
I think it is b, since it seems that since the equation was just multiplied by two, the enthalpy would also be multiplied by 2. (2 * -483.6) = -967.2
I don't know if this is right though. I am consistently getting thrown off by how to determine whether answers should have positive or negative H's.
Answered by
4
Answer:
C
Explanation:
-285.5-2(40.6)=-205.5 kJ /mol
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