Question

2HBr⇔H2+B2
For this reaction equillibrium constant is 2.2×10^-5 calculate the degree of desociation

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Answer 1

Answer:

The equilibrium constant for the dissociation of molecular iodine, 12(g) + 2[/g), at 800 K is Kc =3.1 x 10-5. ... Kpand Ke>. Calculate the value of Kc if you rewrote the equation H2(g) + 12 S2(g) = H2S(g). 3 ... 15.8 The reaction A2+ B2 = 2 AB has an equilibrium constant Kc = 1.5

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