Question

(2i³)² find a and b
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Answer 1

$\star \: \: \rm\underline{\underline{Question}}$

(2i³)² Find a and b.

$\bf \:Concept$

✞︎ Complex Numbers .

$\rightarrow \bf \underline{Answer}$

$\begin{array}{ |c|c |} \hline \:a& - 4 \\ b&0 \\ \hline\end{array}$

$\purple{ \rm \: Solution}$

Primarily Simplify the given imaginary root in the form of a + ib.

$\boxed{ \begin{array}{c}(2i {}^{3}) {}^{2} = 4i {}^{6} \\ = 4(i {}^{2})\ ^{3} \\ \therefore \: i {}^{2} = - 1 \\ = 4( - 1) ^{3} \\ = - 4 \end{array}}$

Now express this in the form of a + ib

$\rm - 4 + 0i$

On comparing , we can obtain the values of a and b

$\therefore \boxed{a = - 4} \quad \boxed{ b = 0}$

Thankyou.