2k+1, 13, 5k-3 are three consecutive terms of an A.P., then k=______.
Answers
Answered by
11
Answer:
we know that 2 b equals to a + c
Step-by-step explanation:
2×13=2k+1+5k-3
26=7k-2
28=7k
hence,k=4
Answered by
7
Answer:
since common difference of an ap is equal so,
13-(2k+1) = 5k-3-13
13-2k-1=5k-16
12+16=7k
k=28÷7
k=4
answer is 4
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