Question

2k+1, 13, 5k-3 are three consecutive terms of an A.P., then k=______.

Answer 1

Answer:

we know that 2 b equals to a + c

Step-by-step explanation:

2×13=2k+1+5k-3

26=7k-2

28=7k

hence,k=4

Answer 2

Answer:

since common difference of an ap is equal so,

13-(2k+1) = 5k-3-13

13-2k-1=5k-16

12+16=7k

k=28÷7

k=4

answer is 4