Question

2k+1,13,5k-3. એક સમાંતર શ્રેણી ના ક્રમિક પદો હોય તો k =____​

Answer 1

Answer:

k=8.333..

Step-by-step explanation:

Answer is as follows

Let t1=2k+1. t2=13. t3=5k-3

Since the given terms are in A.P.

---) t2-t1=t3-t2

---) 13-2k-1=5k-3-11

---) 12-2k=5k-14

---) 5k-2k=14+12

---) 3k=26

---) k=26/3=(approx) 8.333...

I HOPE THIS HELPS YOU