Question

2k-1 ,23 , 5k-2 are in one AP find k value​

Answer 1

Given 2k-1 ,23 , 5k-2 are in AP

let a=2k-1 ,b=23 , c=5k-2

for an AP : 2b = a+c..........................(formula)

                 2(23) = 2k-1 +5k -2

                     46 = 7k - 3

                      49= 7k

                         k = 7

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