Question

(2k+1)(2k+1) - (7k+2) + (7k-3) = 0

Answer 1

(4k² +2k+2k+2)-(49k²-21k+14k-6)=0
(4k²+4k+2)-(49k²-7k-6)=0
4k²+4k+2-49k²+7k+6=0
-45k²+11k+8=0ans

Answer 2

=4k² +2k+2k+2)-(49k²-21k+14k-6)=0
=(4k²+4k+2)-(49k²-7k-6)=0
=4k²+4k+2-49k²+7k+6=0
=-45k²+11k+8=0