Question

2K - 3(K-1) + 5/2 =0
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Answer 1

Answer:

$2k - 3(k - 1) + \frac{5}{2} = 0 \\ 2k - 3k - 3 + \frac{5}{2} = 0 \\ \frac{4k - 6k - 6 + 5}{2} = 0 \\ \frac{ - 2k - 1 }{2} = 0 \\ - 2 k - 1 = 0 \times 2 \\ - 2k - 1 = 0 \\ - 2k = 0 + 1 \\ - 2k = 1 \\ k = \frac{1}{ - 2}$

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