Question

2k-3(k-1)+5\2 =0 find the answer it os in linear equation 8 b​

Answer 1

Answer

We are given that (2K-3,K+2) lies on the line 2x+3y+15=0

Since the given point lies on the line

So, it must satisfy the equation of line .

2(2K-3)+3(K+2)+15=02(2K−3)+3(K+2)+15=0

4K-6+3K+6+15=04K−6+3K+6+15=0

7K+15=07K+15=0

K = \frac{-15}{7}

K= -15/7

Step-by-step explanation:

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