Math, asked by sreejithielts71181, 10 months ago

2k-3(k-1)+5/2=00000000

Answers

Answered by chandrikaprasad23656
4

Answer:

2K-3(K-1)+5/2=0

2K-3K+3+5/2=0

-K+3+5/2=0

-K+1/2=0

-K=-1/2

K=1/2

Step-by-step explanation:

Answered by 01523
0

Answer:

Step-by-step explanation:

2k-3(k-1)+5/2=0

We multiply parentheses

2k-3k+3+5/2=0

We multiply all the terms by the denominator

2k*2-3k*2+5+3*2=0

We add all the numbers together, and all the variables

2k*2-3k*2+11=0

We multiply elements

4k-6k+11=0

We add all the numbers together, and all the variables

-2k+11=0

We move all terms containing k to the left, all other terms to the right

-2k=-11

k=-11/-2

k=5+1/2

k-1/2

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