Question

2K2 - 6k = 0
or
2k(k - 3) = 0.

SOLVE BOTH EUQATIONS....BOTH ARE SEPARATE EQUATIONS SO DON'T ADD THEM​

Answer 1

k2" was replaced by "k^2".

Step by step solution :

STEP

1

:

Equation at the end of step 1

(2k2 - 6k) - 8 = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

2k2 - 6k - 8 = 2 • (k2 - 3k - 4)

Trying to factor by splitting the middle term

3.2 Factoring k2 - 3k - 4

The first term is, k2 its coefficient is 1 .

The middle term is, -3k its coefficient is -3 .

The last term, "the constant", is -4

Step-1 : Multiply the coefficient of the first term by the constant 1 • -4 = -4

Step-2 : Find two factors of -4 whose sum equals the coefficient of the middle term, which is -3 .

-4 + 1 = -3 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and 1

k2 - 4k + 1k - 4

Step-4 : Add up the first 2 terms, pulling out like factors :

k • (k-4)

Add up the last 2 terms, pulling out common factors :

1 • (k-4)

Step-5 : Add up the four terms of step 4 :

(k+1) • (k-4)

Which is the desired factorization

Equation at the end of step

3

:

2 • (k + 1) • (k - 4) = 0

STEP

4

:

Theory - Roots of a product